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01 Magnifying Glass

Aim

To show three ways to use a magnifying glass.

Subjects

Diagram

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Figure 1:.

Equipment

“Eye”:

“Magnifying glass”:

Presentation

On a table there is a piece of text. You stand close to the table. First show what you do when you use a magnifying glass. There are three possible ways:

(a)Hold the lens (+150 mm(+150 \mathrm{~mm} ) very close to your eye and show the students that you have to bend towards the text until you can read it sharp. The distance between lens and text is smaller than flens \mathrm{f}_{\text {lens }} (we measure around 10 cm10 \mathrm{~cm} ).

(b)Hold the lens 15 cm15 \mathrm{~cm} (=f lens ) away from the text, allowing you to relax your eye. When reading your text you still have to bend.

(c)Hold the lens a comfortable distance away from the eye so that you do not have to bend. Adjust the distance between lens and text until a clear enlarged image appears. The lens has to be close to the text now (always a distance smaller than 15 cm15 \mathrm{~cm} ). This is how people mostly use a magnifying glass.

Now we turn to the demonstration set up (see Diagram).

First we use only the “Eye-part” and focus it at an object in the lecture-room far away (infinity): Adjust the iris diaphragm and eye lens position to obtain a clear image on the screen. This situation corresponds to the eye muscles completely relaxed. At this position of the eye lens a marker (1) is placed on the table.

“Eye” and “Object” are each at the outer ends of the optical rail. The lamp is switched on and illuminates the graph paper diffusely. The iris diaphragm and the position of the eye lens are adjusted until a sharp image of the graph paper is seen on the screen. On the screen the distance between the mm-lines of the graph paper is measured (x1)\left(x_{1}\right). This situation corresponds to normally reading a text on the table with an unaided eye: The “Object” is at the so-called near point. Also place a marker (2) at the position of the eye lens in this situation.

(a’)Leaving the eye lens in this position, the magnifying glass is fixed to the eye lens by means of tape. The “Object” is shifted towards the “Eye” + magnifying glass until the image of the graph paper is sharply seen on the screen (the “Eye” again sees the virtual image at the near point). On the screen the distance between the mm-lines of the graph paper is measured (x2)\left(x_{2}\right). The magnification equals (x2/x1)\left(x_{2} / x_{1}\right).

(b’)Again focus the “eye lens” at infinity (the first marked position). In this way the “Eye” will view in a relaxed way. The magnifying glass is positioned 15 cm15 \mathrm{~cm} in front of the object, in order to obtain a virtual image at infinity. The “Object” + magnifying glass combination is shifted towards the “Eye” until the image of the graph paper is sharply seen on the screen. On the screen the distance between the mm-lines is measured (x3)\left(x_{3}\right). The magnification equals x3/x1x_{3} / x_{1}.

(c’)The “Object” is placed at the end of the optical rail and the magnifying glass closer than 15 cm15 \mathrm{~cm} to the object. The eye lens is shifted until a sharp image of the graph paper is seen on the screen. On the screen the distance between the mm-lines is measured (x4)\left(x_{4}\right). The magnification equals x4/x1x_{4} / x_{1}.

Notify the results obtained and discuss them.

Explanation

When no lens is used, the object is at the near point and observed at an angle αu\alpha_{u} (see Figure 2).

When the lens is directly in front of the eye, the image is virtual and erect and must be observed at near point. To have this, the object has to be less than one focal length away from the lens (see Figure 2b). Analysis shows that the angular magnification equals M=αaαu=d0f+1M=\frac{\alpha_{a}}{\alpha_{u}}=\frac{d_{0}}{f}+1

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Figure 2:.

When the lens is placed a distance ff from the object, angular magnification becomes

M=αaαu=d0fM=\frac{\alpha_{a}}{\alpha_{u}}=\frac{d_{0}}{f}

Still the eye is close to the object. (see Figure 2c) (Theoretically a larger distance between magnifying glass and object is possible but then distorsion occurs, since the eyelens sees the imageforming rays no longer paraxial.)

When the object is a comfortable reading distance away analysis shows

M=Lp[1+(fp)dpf]M=\frac{L}{p\left[1+\frac{(f-p) d}{p f}\right]}

(see Figure 2d).

So for maximum magnification the magnifying glass should be hold closely to the eye. To have a more comfortable situation you have to be content with a lower magnification.

Remarks

Sources