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01 Chromatic Aberration

Aim

To show that different “colored” rays traverse a lens along different paths.

Subjects

Diagram

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Figure 1:.

Equipment

Presentation

The lamp and camera are positioned each at the end of the rail. The camera has its lens removed; a .01 grey filter is placed on it. The other components are placed and carefully aligned; see Diagram (use the white screen at the position of the camera).

Using the red interference filter the .3 mm.3 \mathrm{~mm}-diaphragm is pictured on the camera at the end of the optical rail. To get a sharp picture the diaphragm is shifted. The projector projects this image to the students. The red filter is turned away and the yellow filter is now in position. Clearly can be seen that this picture is not sharp. To get it sharp we need to shift the camera towards the lens. The same happens when next we apply the green and then the blue filter. Going from red to blue we need to shift the camera about 20 cm20 \mathrm{~cm} in total. This is clearly observable to the students. And the conclusion can be that the lens has a smaller focal distance for shorter wavelength.

When the 150 mm150 \mathrm{~mm} single lens is replaced by the doublet of 150 mm150 \mathrm{~mm}, changing filters will result in sharp images all at the same position of the camera on the rail: no shifting is needed. There is no chromatic aberration.

Explanation

Since the thin-lens equation 1f=(nt1)(1R11R2)\frac{1}{f}=\left(n_{t}-1\right)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right) is wavelength-dependent via n1(λ)n_{1}(\lambda)

(dispersion), the focal length must also vary with λ\lambda (Figure 2 shows the graph of nn, versus λ\lambda of crown-glass.).

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Figure 2:.

In general n1(λ)n_{1}(\lambda) decreases with wavelength over the visible region, and thus f(λ)f(\lambda) increases with λ\lambda. And when f(λ)f(\lambda) increases with λ\lambda, then also the image-distance increases with λ\lambda (object-distance is constant). The demonstration shows this: the red image being sharp at a larger distance than the blue image.

A negative lens would generate “negative” chromatic aberration. This suggests that a combination of a positive - and a negative lens could result in an overlapping of fred f_{\text {red }} and fblue f_{\text {blue }}. This is the way an achromatic doublet functions.

Remarks

Sources