Skip to article frontmatterSkip to article content

02 Fire-Pump

Aim

To show that fast compression is accompanied by a considerable raise in temperature.

Subjects

Diagram

.

Figure 1:.

Equipment

Presentation

Small pieces of pyroxyl are put in the tube. The plunger is fitted into the tube and then pushed down rapidly. The pyroxyl lights and burns with a flash (see DiagramB). This points out to a steep increase in temperature.

Explanation

In general the process of the gas is polytropic, so: pVn=p V^{n}= constant. In this demonstration the air in the closed tube is compressed rapidly, so during this action there is almost no heat exchanged with the surroundings. Such a process is performed adiabatically, and n=γn=\gamma, giving pVγ=p V^{\gamma}= constant. Rewriting this in terms of temperature gives: TVγ1=T V^{\gamma-1}= constant and so: T2=(V1V2)γ1T1T_{2}=\left(\frac{V_{1}}{V_{2}}\right)^{\gamma-1} T_{1}.

When the compression ratio (V1V2)\left(\frac{V_{1}}{V_{2}}\right) is around 6 and using air (γ=1.4)(\gamma=1.4) we have: T2=60.4T_{2}=6^{0.4}.

T1=2T1T_{1}=2 T_{1}. So starting at room temperature ( T1=300 KT_{1}=300 \mathrm{~K} ), the air should heat up to around 600 K(327C)!600 \mathrm{~K}\left(327^{\circ} \mathrm{C}\right)!

Remarks

(p2=(V1V2)γp1=61.4=12bar)\left(p_{2}=\left(\frac{V_{1}}{V_{2}}\right)^{\gamma} p_{1}=6^{1.4}=12 b a r\right)

Sources