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01 Clement’s and Desormes’ Experiment

Aim

Subjects

Diagram

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Figure 1:.

Equipment

Presentation

The valve of the container is closed. By means of the syringe an amount of air is pushed into the container. The manometer shows the raised pressure in the container (h1)\left(h_{1}\right). Now the valve of the container is opened for a short time (just long enough to have the pressure in- and outside the container to be equal; about is in our situation). After closing the valve, the manometer shows that the pressure inside the container rises and after some time reaches a fixed value (h2)\left(h_{2}\right).

The ratio of heat capacities, Cρ/CVC_{\rho} / C_{V} can now be determined by γ=CpCV=h1h1h2\gamma=\frac{C p}{C V}=\frac{h_{1}}{h_{1}-h_{2}}

Explanation

The air in the container and syringe is at room temperature T0T_{0} and pressure p0p_{0}. Pressing the syringe raises the pressure to p1p_{1}. The manometer reads h1h_{1}. (See Figure 2.)

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Figure 2:.

Opening the valve makes the air expand adiabatically to pressure p0p_{0} and temperature falls to T2T_{2}. The valve is quickly closed and now the trapped air in the container raises isochorically in temperature to T0T_{0} and pressure p3p_{3}. The manometer reads h2h_{2}. Consider the isothermic - and adiabatic process:

Isothermic: pV=p V= const. Vdp+pdV=O(dydV)i=pVV d p+p d V=O\left(\frac{d y}{d V}\right)_{i}=-\frac{p}{V}

Adiabatic: pVr=p V^{r}= const., Vrdp+pVr1dV=0,(dpdV)a=γpVV^{r} d p+p V^{r-1} d V=0,\left(\frac{d p}{d V}\right)_{a}=-\gamma \frac{p}{V}

These two combined: (dpdV)a=γ(dpdV)i\left(\frac{d p}{d V}\right)_{a}=\gamma\left(\frac{d p}{d V}\right)_{i}

Consider this for the same dVd V in both processes (see Figure 2) and we find:

dpadpi=γ=h1h1h2\frac{d p_{a}}{d p_{i}}=\gamma=\frac{h_{1}}{h_{1}-h_{2}}

Remarks

Sources