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03 Young’s Double Slit

Young’s double slit

Aim

To show a double slit interference pattern and the influence of slit-separation.

Subjects

Diagram

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Figure 1:.

Equipment

Safety

Presentation

Preparation

The demonstration is set up as shown in Diagram:

-The two mirrors are positioned in such a way that the laser beam passes parallel to the table.

-The two lenses ( +10 mm+10 \mathrm{~mm} and +50 mm+50 \mathrm{~mm} ) are positioned at an intermediate distance of 60 mm60 \mathrm{~mm}. Having passed these lenses, the laser beam is broadened (and a little divergent). Take care that the broadened beam is still parallel to the table.

-The lens of 132 mm132 \mathrm{~mm} can easily be shifted in this beam up and down using the carefully positioned guidance rail.

Demonstration

The set-up as described in Preparation is shortly explained to the students. The most important in this explanation is that the double slit will be placed in a broadened beam and that the double slit will be illuminated by plane waves.

The slide with the double slits is placed on an overhead projector, so the students can see the configuration. The dimensions are indicated on an overhead sheet that is projected at the same time.

The laser is switched on, the broadened beam projects on the wall. When the +132 mm+132 \mathrm{~mm} lens is placed at the end of the table, this spot is enlarged (see Figure 2A; the diameter of the projected spot is around 1 m1 \mathrm{~m} ). Then the double slit is shifted into the beam starting with configuration a (see Equipment).

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Figure 2:.

The typical interference pattern appears (see Figure 2B; Figure 2C shows a snapshot of a real projection on the wall). Then we shift to configuration b\mathbf{b}, then b\mathbf{b} and finally b\mathbf{b}; in that way going from large to smaller slit-separation. It is observed that with smaller slitseparation the distance between the lines of interference increases

Explanation

Young explained the observed pattern with the Huygens wave theory and so introduced the principle of interference. Many textbooks give the explanation. Figure 3 shows the arrangement: ss is very large compared to the slit separation bb.

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Figure 3:.

In PP, ray r1r_{1} and ray r2r_{2} interfere. This interference will be constructive when r1r2=mλr_{1}-r_{2}=m \lambda (m=0,1,2,3,)(m=0,1,2,3, \ldots).

Also ymsbmλy_{m} \approx \frac{s}{b} m \lambda, and the difference in position of two constructive maxima is Δysbλ\Delta y \approx \frac{s}{b} \lambda, explaining the equidistance between the observed maxima and the influence of bb in consistency with what we saw in the Presentation. Interference term

Remarks

intensity (/)(/) at P:I(θ)[sin(πasinθλ)πasinθλ]2 Diffraction  envelop term ×cos2(πbsinθλ) Interference  term \mathrm{P}: I(\theta) \approx \underbrace{\left[\frac{\sin \left(\frac{\pi a \sin \theta}{\lambda}\right)}{\frac{\pi a \sin \theta}{\lambda}}\right]^{2}}_{\begin{array}{c}\text { Diffraction } \\ \text { envelop term }\end{array}} \times \underbrace{\cos ^{2}\left(\frac{\pi b \sin \theta}{\lambda}\right)}_{\begin{array}{c}\text { Interference } \\ \text { term }\end{array}}

If a becomes vanishingly small, then the diffraction envelope term approaches 1 , and only interference is present. This is the condition for a good Young’s double slit experiment. With a=.20 mma=.20 \mathrm{~mm} this appears to work satisfactory. Using double slits with larger a, then next to interference also diffraction becomes visible in our set-up and that is a different demonstration.

Sources