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01 Centre of Mass

Aim

To show that the centre of mass does not change when only internal forces act.

Subjects

Diagram

Diagram of the experimental set-up

Figure 1:Diagram of the experimental set-up

Equipment

Safety

Presentation

The Diagram is shown to the students. Then the mass of the cart-assembly is measured by the balance (4 kg4 \mathrm{~kg}) and also that of the steel ball (1 kg1 \mathrm{~kg}). Next, the centre of mass of the cart-assembly is determined by balancing this assembly on the small wooden beam. Then the assembly is set at rest in the middle of the levelled cart-track, and the pointer is fixed to the assembly in its centre of mass. Furthermore, this pointer position is marked on the table by placing a piece of chalk upright.

Schematic representation of the experimental setup

Figure 2:Schematic representation of the experimental setup

The steel ball is placed at the slope of the bent track. We place it about 33 cm33 \mathrm{~cm} away from the point of reference on the assembly. With our other hand, we hold the cart assembly in its resting position. The ball is released and rolls down the track. The whole assembly is moving, and the steel ball is captured in the plastic coffee cup (a small piece of modelling clay at the low side at the entrance of the cup takes care that the steel ball remains in the cup). This plastic cup is 67 cm67 \mathrm{~cm} away from the centre of mass of the cart-assembly.

When the ball is caught, the whole assembly is immediately at rest. However, the whole assembly is shifted (about) 20 cm20 \mathrm{~cm} to the side where the ball came from (see the pictures in the diagram, where the actual displacement is larger due to the higher starting point of the steel ball).

Explanation

Our steel ball has a mass of 1 kg1 \mathrm{~kg}. The cart-assembly (with carts, track, and cup, etc.) has a mass of 4 kg4 \mathrm{~kg}. With our starting position at 33 cm33 \mathrm{~cm} away from the point of reference, this gives a sketch of the situation as shown in the first picture of Figure 2.

Calculating the distances xx and yy gives the displacement of the cart-assembly: With mm being the mass of the steel ball and 4m4 m the mass of the cart-assembly, the centre of mass is at the position indicated by the dotted line, because by definition the centre of mass is positioned at R=m1r1+m2r2m1+m2R=\frac{m_{1} r_{1}+m_{2} r_{2}}{m_{1}+m_{2}}, relative to some origin. When that origin is taken at the dotted line, so R=0R=0, we have: R=1(x.33)+4(x)1+4=0R=\frac{1(x-.33)+4(x)}{1+4}=0, making x=6.6 cmx=6.6 \mathrm{~cm}. When the steel ball is released, no external forces act upon it, meaning that the centre of mass will not move. The bottom picture in Figure 2 shows the situation at the end and the displacement of the steel ball and cart-assembly.

Calculating again the position of the centre of mass in the same way

R=1(.67y)4(y)1+4=0R=\frac{1(.67-y)-4(y)}{1+4}=0

yielding y=13.5 cmy=13.5 \mathrm{~cm}. So the total displacement of the assembly equals 6.6+13.5=20.1 cm6.6+13.5=20.1 \mathrm{~cm}. This is confirmed in our demonstration.

Remarks

Sources