Skip to article frontmatterSkip to article content

01 Going Round in Circles

Aim

To see/feel the centripetal force.

Subjects

Diagram

.

Figure 1:.

Equipment

Presentation

The diagram shows the components and how to use them. By swinging the tube slightly, the mass m1m_{1} begins to move in circles above your head. The demonstrator must swing m1m_{1} at a specific frequency to balance the system.

.

Figure 2:.

If time permits, the relationship between the variables in this demonstration can be verified more exactly. Just below the tubing, a paperclip is fixed to the rope used as a marker to make m1m_{1} go round in a circle with fixed RR. A stopwatch can be used to time the frequency.

  1. When m1m_1 is doubled by adding another rubber stopper to it, a lower frequency is needed to balance the system.

  2. When m2m_{2} is increased, a higher frequency is needed to balance the system.

  3. When half the rope length is used (shifting the paperclip), a higher frequency is needed to balance the system.

Explanation

Analysis shows that movement at a constant speed ( vv ) of a mass ( m1m_{1} ) in a circle with radius RR can be described by ac=v2rω2Ra_{c}=\frac{v^{2}}{r} \omega^{2} R. In our demonstration the tension ( TT ) in the string provides the force needed for ac:T=m1aca_{c}: T=m_{1} a_{c}, and m2g=m1acac=m2m1gm_{2} g=m_{1} a_{c} \Rightarrow a_{c}=\frac{m_{2}}{m_{1}} g, (see Figure 3).

.

Figure 3:.

  1. Doubling m1m_1 means that the centripetal acceleration aca_c provided by the string tension will be halved (ac=m2m1g)\left(a_c = \frac{m_2}{m_1} g\right). To keep m1m_1 moving in the same circle, ω\omega must decrease by a factor of 2\sqrt{2} according to (ac=ω2R)\left(a_c = \omega^2 R\right).

  2. Increasing m2m_2 raises the string tension, so the provided aca_c increases (T=m1ac)\left(T = m_1 a_c\right). To keep m1m_1 moving in the same circle, ω\omega has to increase.

  3. When RR is halved but the tension in the string remains the same, the provided aca_c also remains constant. To keep m1m_1 moving in a (smaller) circle, ω\omega must increase by a factor of 2\sqrt{2} according to (ac=ω2R)\left(a_c = \omega^2 R\right).

Remarks

Sources