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04 Parallel Wires

Aim

To show that parallel wires attract or repel depending on the current direction.

Subjects

Diagram

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Figure 1:.

Equipment

Presentation

The two long wires are suspended from one clamp, close to the rigid white screen. One of the wires is also clamped at the lower end of the white screen and stretched. The second wire is hanging freely in such a way that at the lower end it is about 2 cm2 \mathrm{~cm} seperated from the fixed wire (see Diagram and Figure 2A).

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Figure 2:.

Parallel wires

The wiring is set up in such a way that both wires conduct the current in the same direction (Figure 2A). When switching on the current we see that the “loose” wire moves closer to the fixed wire.

Then the wiring is changed so that the two wires conduct the current in opposite directions (Figure 2B). Switching on the current now shows that the “loose” wire is moving away from the fixed wire.

Explanation

The magnetic induction around a current-carrying wire equals: B(r)=μ0I12πrB(r)=\frac{\mu_{0} I_{1}}{2 \pi r} and is directed circularly around that wire (corkscrew). The force on a current in a magnetic field equals F=I2lB(r)F=I_{2} l B(r) and is directed perpendicular to I2I_{2} and B.v0B . v_{0} being 4π.107Hm4 \pi .10^{-7} \mathrm{Hm}^{-}

1{ }^{1} leads to F=2.107I1I2lrF=2.10^{-7} \frac{I_{1} I_{2} l}{r}.

Applying the rigth-hand rule shows the direction of this force between current I1(B)I_{1}(B) and I2I_{2} (see Figure 3).

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Figure 3:.

Calculating F\mathrm{F} for every 1 cm1 \mathrm{~cm} length of wire we find:

So, in this demonstration the force on the wires is very small.

Remarks

Sources