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05 Pendulum of Death

Aim

To show that we really trust the law of conservation of energy.

Subjects

Diagram

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Figure 1:.

Equipment

Presentation

A long pendulum is suspended from the ceiling of the lecturehall. The pendulum bob is a heavy cast-iron sphere. The demonstrator draws the bob to one side and puts his head immediately adjacent to it and steadies himself against some support. Then he releases the ball, and keeping his eyes fixed on the audience, he explains that he is willing to risk his head to demonstrate that the law of conservation of energy applies! Meanwhile, the ball has been swinging far out, and is returning to his head threateningly. But the ball slows down as it regains its original level and barely touches the head. The law of conservation of energy has given a correct prediction: the demonstrator survives.

Explanation

Mechanical work done by a field force in moving a body between AA and BB is defined as: WAB=ABFds=U(rA)U(rB)W_{A B}=\int_{A}^{B} \vec{F} d\vec{s}=U\left(\vec{r}_{A}\right)-U\left(\vec{r}_{B}\right), (independent of the path taken: conservative force field). U(r)U(\vec{r}) is called the potential energy function.

Also can be shown (using F=ma\vec{F}=m \vec{a} ) that ABFds=12mvB212mvA2=KBKA.K\int_{A}^{B} \vec{F} d \vec{s}=\frac{1}{2} m v_{B}^{2}-\frac{1}{2} m v_{A}^{2}=K_{B}-K_{A} . K is called: kinetic energy.

Combining these two equations: UA+KA=UB+KBU_{A}+K_{A}=U_{B}+K_{B}.

So the pendulum bob moves in such a way that U+K=E=U+K=E= constant. On release the bob has only potential energy E=UAE=U_{A}. When it returns to its original height it has the same amount of potential energy, so then K=0K=0, and v=0v=0. Reaching a point higher than A\mathrm{A} should mean that EE has to increase, which violates U+K=E=U+K=E= constant.

Remarks

Video Rhett Allain

Video embedded from https://www.youtube.com/rhettallain/videos, courtesy Rhett Allain.

Sources