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06 Sleeper

Aim

To show how a spinning top rises itself to a vertical spin

Subjects

Diagram

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Figure 1:.

Equipment

Presentation

When the top slows down, it increases its angle with the vertical and finally topples down (see the last part of the track in Diagram).

Explanation

The top, being almost a free body, moves around its centre of mass (CM), which remains stationary.

Due to its tilted position, the spinning top will precess ( I0ω0I_{0} \omega_{0} moves into the direction of gravitational torque TpT_{p}, see Figure 2a.).

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Figure 2:.

As a result the rounded stem of the top is attempting to roll over the floor in two ways: one due to the spin of the top around its body-axis and the other due to precession driving the stem over the floor. The first way is much faster than the second and so the rounded stem slips: it slips into the direction of spin. The friction force on the stem in point C\mathrm{C} is opposite to the slip, so friction is directed backwards (see Figure 2b). The torque of this friction force ( TfT_{f} ) is almost perpendicular to I0ω0I_{0} \omega_{0}, so I0ω0I_{0} \omega_{0} continues to rise until the top is positioned vertical ( TfT_{f} will tend to align Ioω0I_{o} \omega_{0} ). The orientation of the top follows that of I0ω0I_{0} \omega_{0}, and the top rights itself.

Once perfectly vertical the friction force is no longer present, but any disturbance moving the top away from the vertical immediately introduces a raising torque again, restoring its vertical position.

While moving to the vertical the track of precession will have a smaller radius of curvature, so while raising, we will see a converging spiral ending in a point.

Due to dissipation the spin of the top is slowed down and a point will be reached when slipping stops. Consequently the raising torque is no longer present: the top topples.

Remarks

Sources