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06 Sleeper

Updated: 09 Jul 2026

Aim

To show how a spinning top rises itself to a vertical spin

Subjects

Diagram

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Figure 1:.

Equipment

Presentation

When the top slows down, it increases its angle with the vertical and finally topples down (see the last part of the track in Diagram).

Explanation

The top, being almost a free body, moves around its centre of mass (CM), which remains stationary.

Due to its tilted position, the spinning top will precess ( I0ω0I_{0} \omega_{0} moves into the direction of gravitational torque TpT_{p}, see Figure 2 A.).

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Figure 2:.

As a result, the rounded stem of the top tends to roll over the floor in two distinct ways: one caused by the top spinning about its body axis, and the other caused by precession moving the stem across the floor. Since the first motion is much faster than the second, the rounded stem slips, with the slipping occurring in the direction of spin. The friction force on the stem in point C\mathrm{C} is opposite to the slip, so friction is directed backwards (see Figure 2 B). The torque of this friction force ( TfT_{f} ) is almost perpendicular to I0ω0I_{0} \omega_{0}, so I0ω0I_{0} \omega_{0} continues to rise until the top is positioned vertical ( TfT_{f} will tend to align Ioω0I_{o} \omega_{0} ). The orientation of the top follows that of I0ω0I_{0} \omega_{0}, and the top rights itself.

Once perfectly vertical the friction force is no longer present, but any disturbance moving the top away from the vertical immediately introduces a raising torque again, restoring its vertical position.

While moving to the vertical the track of precession will have a smaller radius of curvature, so while raising, we will see a converging spiral ending in a point.

Due to dissipation the spin of the top is slowed down and a point will be reached when slipping stops. Consequently the raising torque is no longer present: the top topples.

Remarks

Sources